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RLC circuit

RLC circuit: the circuit drawn with the example's values10 Ω1mH1µF
F0 = 5.03 kHz, Q = 3.16, series: 10 Ω, 1 mH, 1 µF

The resistor decides how long an LC keeps ringing; Q counts the swings.

Opens in the app on 1 December, with Circuit Notebook 1.0 See it worked out

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The example, worked out

Given

Arrangement
R, L and C in series
Resistance R
10 Ω
Inductance L
1 mH
Capacitance C
1 µF
Frequency of interest
5 kHz

Working

  1. the same in series and in parallel
  2. a small R lets it ring
  3. at 5 kHz

Results

Resonance f05.03 kHz
Quality factor Q3.16
Bandwidth f0 / Q1.59 kHz
Damping ζ0.158: under-damped
|Z| at f010 Ω
|Z| at 5 kHz10 Ω
Z0 = √(L/C)31.6 Ω

The formulas

  1. f0 = 1 / (2π √(L C))the same for both
  2. Q = Z0 / R (series), R / Z0 (parallel)the resistor damps one and loads the other
  3. BW = f0 / Qbetween the two half-power points

The usual traps

  • In series the impedance is lowest at f0; in parallel it is highest.
  • Q above 0.5 (ζ below 1) means it rings on a step: the overshoot grows fast with Q.
  • The coil's own resistance counts as part of R.

Questions

How do I calculate the resonance and Q of an RLC circuit?

f0 = 1 / (2π √(L C)): the same for both. Q = Z0 / R (series), R / Z0 (parallel): the resistor damps one and loads the other. BW = f0 / Q: between the two half-power points.

What does it give for typical values?

F0 = 5.03 kHz, Q = 3.16, series: 10 Ω, 1 mH, 1 µF. Resonance f0: 5.03 kHz; Quality factor Q: 3.16.

What are the usual mistakes?

In series the impedance is lowest at f0; in parallel it is highest. Q above 0.5 (ζ below 1) means it rings on a step: the overshoot grows fast with Q. The coil's own resistance counts as part of R.

In the app

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The part you can buy

Results rounded to standard values (E12, E24, E96) and power ratings.

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Opens in the app on 1 December, with Circuit Notebook 1.0

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