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The example, worked out
Given
Resistance R
10 kΩ
Capacitance C
100 nF
Step voltage
5 V
Level of interest
50 %
Working
ohms times farads are seconds
where a filter made of them is 3 dB down
to reach 50 % of the step
Results
Time constant τ1 ms
Cutoff (−3 dB)159 Hz
To 50 % (2.5 V)693 µs
To 63 % (τ)1 ms
To 95 % (3 τ)3 ms
To 99 % (5 τ)5 ms
The formulas
τ = R × Cohms times farads are seconds
fc = 1 / (2π R C)where the RC filter is 3 dB down
t = −τ ln(1 − x)the time to reach the share x of the step
The usual traps
63 % at one τ, not 100 %: five τ for 99 %.
Charging and discharging take the same time.
Questions
How do I calculate the time constant of an RC circuit?
τ = R × C: ohms times farads are seconds. fc = 1 / (2π R C): where the RC filter is 3 dB down. t = −τ ln(1 − x): the time to reach the share x of the step.
What does it give for typical values?
Τ = 1 ms, fc = 159 Hz with 10 kΩ and 100 nF. Time constant τ: 1 ms; Cutoff (−3 dB): 159 Hz.
What are the usual mistakes?
63 % at one τ, not 100 %: five τ for 99 %. Charging and discharging take the same time.
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Open the calculatorOpens in the app on 1 December, with Circuit Notebook 1.0