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The example, worked out
Given
Stage
Non-inverting
Gain wanted (V/V)
10
R1 + R2 around
100 kΩ
Standard series
E24 (5 %)
Gain-bandwidth product
1 MHz
Slew rate
0.5 V/µs
Output swing wanted
8 V
Working
one plus the ratio
the noise gain eats the bandwidth, for both stages
the slew rate limit at full swing
Results
R120 kΩ
R2 (feedback)180 kΩ
Gain you get10 V/V (20 dB)
Bandwidth (−3 dB)100 kHz
Full-power bandwidth19.9 kHz
Input resistancevery high
The formulas
G = 1 + R2 / R1 (non-inverting), G = −R2 / R1 (inverting)two resistors set the gain
f−3dB = GBW / (1 + R2 / R1)the noise gain eats the bandwidth
fmax = SR / (π Vpp)the slew rate limit at full swing
The usual traps
A gain of 100 on a 1 MHz op-amp leaves 10 kHz of bandwidth.
Large signals turn into triangles long before small ones roll off.
Questions
How do I choose the resistors for an op-amp gain?
G = 1 + R2 / R1 (non-inverting), G = −R2 / R1 (inverting): two resistors set the gain. f−3dB = GBW / (1 + R2 / R1): the noise gain eats the bandwidth. fmax = SR / (π Vpp): the slew rate limit at full swing.