Power calculator

Linear regulator heat

Linear regulator heat: the circuit drawn with the example's values5 VINOUTGND10uF10uF12 V5 V
2.16 W of heat, 41 %, Tj 155 °C (12 V → 5 V at 300 mA)

A linear regulator is a smart resistor: the extra volts become heat.

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The example, worked out

Given

Input
12 V
Output
5 V
Load current
300 mA
Quiescent current
5 mA
Thermal resistance to air
60 °C/W
Air temperature
25 °C

Working

  1. the volts dropped times the current, plus what it eats itself
  2. useful power over power drawn
  3. heat flows like a current through a thermal resistance

Results

Heat in the regulator2.16 W
Junction temperature154.6 °C
Efficiency41 %
Power to the load1.5 W
Headroom (Vin − Vout)7 V

The formulas

  1. P = (Vin − Vout) × Iout + Vin × Iqthe volts dropped times the current
  2. η = Vout × Iout / (Vin × (Iout + Iq))roughly Vout / Vin
  3. Tj = Ta + P × RθJAheat flows like a current

The usual traps

  • 12 V to 5 V at 1 A: 7 W of heat, a heatsink or a buck.
  • Too little headroom: a 7805 needs 2 V, an LDO a few hundred millivolts.

Questions

How hot does a linear regulator get?

P = (Vin − Vout) × Iout + Vin × Iq: the volts dropped times the current. η = Vout × Iout / (Vin × (Iout + Iq)): roughly Vout / Vin. Tj = Ta + P × RθJA: heat flows like a current.

What does it give for typical values?

2.16 W of heat, 41 %, Tj 155 °C (12 V → 5 V at 300 mA). Heat in the regulator: 2.16 W; Junction temperature: 154.6 °C.

What are the usual mistakes?

12 V to 5 V at 1 A: 7 W of heat, a heatsink or a buck. Too little headroom: a 7805 needs 2 V, an LDO a few hundred millivolts.

In the app

Your circuit, drawn live

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The part you can buy

Results rounded to standard values (E12, E24, E96) and power ratings.

The working, shown

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Opens in the app on 1 December, with Circuit Notebook 1.0

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